![]() On the top of that you can create your matrix of smaller. Sharey_ax = _get_share_ax(sharex, axarr, row, col)Īx= fig. An idea is to create three big subplots, to give each of them a title, and make them invisible. Sharex_ax = _get_share_ax(sharex, axarr, row, col) You would have to draw text outside of the plots. If included, there must be one title for each row.ĭict with kewords passed to the `~_title` function.Ī common use is row_title_kw=')įig, big_axes = plt.subplots(nrows, 1, **fig_kw)įor (row, big_ax) in enumerate(big_axes):īig_ax.set_title(str(row_titles), **row_title_kw)īig_ax.tick_params(labelcolor=(1.,1.,1., 0.0), top='off', bottom='off', left='off', right='off')Īxarr = np.empty((nrows, ncols), dtype='O') 131 What's the best practise to add a row and a column header to a grid of subplots generated in a loop in matplotlib I can think of a couple, but not particularly neat: For columns, with a counter to your loop you can use settitle () for the first row only. Number of rows/columns of the subplot grid ![]() Sns.distplot(row_to_fn(size=200), ax=ax)ĭef _get_share_ax(share_var, axarr, row, col):ĭef subplots_with_row_titles(nrows, ncols, row_titles=None, row_title_kw=None, sharex=False, sharey=False, subplot_kw=None, grid_spec_kw=None, **fig_kw):Ĭreates a figure and array of axes with a title for each row. ![]() Row_to_fn = įig, axarr = subplots_with_row_titles(rows, cols, figsize=(cols*8, rows*6), The result looks like this:Įxample usage: import matplotlib.pyplot as plt It returns the same figure and axis array that subplots does with the row titles already included. The code is a riff on () with an additional argument for row titles. Sharing it here in case it saves others time. I’ve had to google for this enough times now to know I should just write a function.
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